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| # | Post Title | Result Info | Date | User | Forum |
| Answer to: DMM in mA mode causes ~0.6 V drop — normal burden voltage? How can I minimize it? | 13 Relevance | 6 months ago | nathan | Theoretical questions | |
| Yes, the 0.6 V Drop you’re seeing is the meter’s burden voltage, which is the voltage lost across the DMM when it measures current. In mA mode, the meter places a small internal shunt resistor (and often a fuse or protection components) in series with your circuit to sense current, and this resistance causes a voltage Drop equal to V=I×Rmeter. For example, a 0.6 V Drop at 60 mA means the meter adds about 10 Ω in series, which can significantly affect low-voltage circuits by reducing the actual voltage reaching your load. To minimize this, you can use an external low-value shunt resistor and measure the voltage across it with the DMM in voltage mode, then calculate current using I=V/RI = V/RI=V/R. Alternatively, use a dedicated low-burden current sense amplifier or sensor such as the INA219, a DC clamp probe that measures current without inserting resistance, or the meter’s 10 A input (which usually has much lower internal resistance) if the current is within safe limits. These methods help keep the measurement accurate without disturbing the circuit’s operating voltage. | |||||
| Answer to: How do I interface a 4–20 mA industrial sensor with an Arduino? | 9 Relevance | 10 months ago | TechSpark | Arduino | |
| ... voltage Drop resistor. The most widely used value is 250 Ω, because it maps the 4–20 mA current range to exactly 1–5 V, which fits perfectly within the Arduino's 0–5 V analog input range. This WAy, 4 mA gives a 1 V Drop, and 20 mA gives a 5 V Drop across the resistor. The sensor typically has two wires: one connects to the +24 V power supply, and the other connects to one side of the 250 Ω resistor. The other side of that resistor goes to GND, which must be shared with the Arduino. To measure the voltage, the analog pin is connected to the node between the ... | |||||
| DMM in mA mode causes ~0.6 V drop — normal burden voltage? How can I minimize it? | 7 Relevance | 7 months ago | JannikTechy | Theoretical questions | |
| I’m measuring the current draw of a low-voltage load and noticed my handheld DMM, in mA mode, is Dropping about 0.6 V across itself. Is that normal “burden voltage,” and what’s the best WAy to reduce it? | |||||
| RE: Linear voltage regulators Vs Switching voltage regulators? | 5 Relevance | 2 years ago | LogicLab | Theoretical questions | |
| @ankunegi I didn’t realize linear regulators were so inefficient when there’s a big voltage Drop. No wonder some of my projects got pretty hot! Switching regulators do sound more efficient, especially for something like a 12V to 5V Drop. The only thing that worries me is the extra complexity with the inductors and noise. | |||||
| What’s the practical limit on daisy-chaining shift registers? | 3 Relevance | 9 months ago | Nitin arora | Theoretical questions | |
| I know that shift registers like the 74HC595 can be daisy-chained to expand outputs, but I’m wondering where the practical limit lies. Is the limit mainly due to propagation delay and timing issues, or do factors like power consumption, loading on the data and clock lines, and signal integrity also become major concerns as the chain gets longer? Are there any general guidelines (such as maximum number of devices or total outputs) before performance or reliability starts to Drop? I’d be interested to hear from anyone who has pushed the number of chained shift registers in a real project. | |||||
| Answer to: Measuring current with oscilloscope? | 3 Relevance | 1 year ago | Sebastian | Equipments | |
| Yes, you can use an oscilloscope with a current probe for the best accuracy and convenience. Alternatively, you can use a shunt resistor in series and measure the voltage Drop to calculate current (I=V/R). | |||||
| Answer to: Measuring current with oscilloscope? | 3 Relevance | 1 year ago | Jaden | Equipments | |
| An oscilloscope, a device primarily designed for voltage measurements, can also be effectively used to measure current. One method involves employing a shunt resistor, a low-resistance component placed in series with the circuit. By measuring the voltage Drop across this resistor, which is directly proportional to the current flowing through it according to Ohm's Law (V = IR), the current value can be determined. Alternatively, a current probe can be utilized. This specialized tool directly senses the magnetic field generated by the current flow and converts it into a proportional voltage, which is then displayed by the oscilloscope. | |||||
| Answer to: Linear voltage regulators Vs Switching voltage regulators? | 7 Relevance | 2 years ago | Admin | Theoretical questions | |
| ... the more energy is WAsted. But they are super easy to use—just a few capacitors and you're good to go. Perfect for quick projects where you don’t need high efficiency. Switching regulators (like the LM2596) switch the input voltage on and off at high speeds, and use inductors/capacitors to store and release energy efficiently. Because of this, they are highly efficient—usually 80% or better. This makes them a great choice for battery-powered projects or situations where you need to Drop a lot of voltage without WAsting power. But they’re a bit more complic ... | |||||
| Answer to: Zener Diode vs. Schottky Diode: What Are the Key Differences? | 5 Relevance | 1 year ago | Sebastian | Theoretical questions | |
| Zener and Schottky diodes protect circuits differently. Zener diodes use reverse voltage avalanche breakdown to clamp voltage at a precise value, determined during production. For example, a 12V Zener diode stabilizes voltage at 12V by conducting in reverse when this level is exceeded. In contrast, Schottky diodes limit voltage through forward conduction, starting to conduct when the voltage exceeds their low forward voltage Drop, typically 0.2–0.4V. Zener diodes offer precise overvoltage protection, while Schottky diodes clamp voltage relative to their forward Drop, serving different applications. | |||||
| Answer to: Zener Diode vs. Schottky Diode: What Are the Key Differences? | 5 Relevance | 1 year ago | LogicLab | Theoretical questions | |
| Zener diodes and Schottky diodes are designed for different purposes and have unique characteristics that suit specific applications in electronic circuits. Zener Diode Function: Primarily used for voltage regulation. Operates in reverse bias when the voltage exceeds a specific breakdown level, known as the Zener voltage. Construction: Made by heavily doping a p-n junction to create a stable breakdown region. Characteristics: Operates in reverse breakdown mode to maintain a constant output voltage despite current variations. More sensitive to temperature changes, which can affect the Zener voltage. Applications: Voltage regulation. Reference voltage sources. Over-voltage protection. Schottky Diode Function: Designed for fast switching and low forward voltage Drop applications. Commonly used in high-speed and power efficiency circuits. Construction: Formed by creating a metal-semiconductor junction, typically with an n-type semiconductor. Characteristics: Low forward voltage Drop (around 0.2–0.3V compared to 0.7V in silicon diodes). Faster switching capabilities. Lower reverse breakdown voltage, which limits its ability to handle high reverse voltages. Applications: Power supplies. RF circuits. Rectifiers in solar panels and high-frequency devices. | |||||
| Answer to: What is the need of connecting a resistor with LDR for Arduino interfacing? | 5 Relevance | 2 years ago | Admin | Hardware/Schematic | |
| If you connect the LDR directly to 5V and the analog pin, there would be no voltage Drop across the LDR irrespective of its resistance value. The analog pin would always read a constant 5V because there is no reference point to indicate a change in resistance. To detect the change in resistance of the LDR, the voltage at the analog pin should change accordingly. This is done using a voltage divider circuit. In the voltage divider circuit, as the resistance of the LDR changes with change in light intensity, the voltage Drop across it changes as well. The analog pin, connected to the point between the LDR and the fixed resistor, reads this changing voltage. This allows the Arduino to continuously register and interpret the varying light levels. | |||||
| Answer to: Why Use a DC Motor Controller Instead of a Potentiometer? | 3 Relevance | 2 years ago | TechSpark | Circuits and Projects | |
| You can use potentiometers for smaller projects, but for bigger projects that need precise control, a potentiometer isn’t the best choice. It causes a significant voltage Drop, which limits the power delivered to the motor. In contrast, motor controllers use PWM to deliver maximum power efficiently. | |||||
| Answer to: Why Fluke multimeters are so expensive? | 3 Relevance | 6 months ago | maryjlee | Equipments | |
| ... etc. Tough housing, Drop-tests, high-CAT safety ratings. High accuracy, true-RMS, stable calibration. Long lifespan, support and WArranty which reduce long-term cost. If you’re replacing a hobby-meter and don’t work in heavy duty applications, yes you might be fine with a cheaper brand. But if you need one tool that you can trust under serious conditions, the extra cost makes sense. | |||||
| Answer to: Can Raspberry Pi Replace a Home Router or Firewall? | 3 Relevance | 6 months ago | Divyam | RPi Pico | |
| Yes, it’s definitely possible to turn a Raspberry Pi (especially Pi 4 or Pi 5) into a router or firewall using software like OpenWRT, Pi-hole, or pfSense (via ARM builds). The Pi 4/5’s Gigabit Ethernet and USB 3.0 ports allow decent throughput—around 600–900 Mbps in real-world tests—suitable for small to medium networks. However, it lacks hardware NAT acceleration and enterprise-grade security features, so performance may Drop under heavy traffic or multiple VPN connections. For basic routing, ad-blocking, and light firewall duties, it’s reliable and stable; for high-load or mission-critical use, a dedicated router or firewall appliance is still preferable. | |||||
| RE: Why Place Decoupling Caps Near ICs? | 3 Relevance | 6 months ago | xecor | Theoretical questions | |
| @electronic_god The 0.1 µF decoupling capacitor placed near an IC’s power pin serves to provide immediate energy and absorb high-frequency noise when the chip’s current demand suddenly changes. When an IC switches states, it draws a short burst of current. If that current must travel from a distant power source through long PCB traces, the inductance and resistance of those traces cause a brief voltage Drop, leading to supply fluctuations or even logic errors. A small capacitor located right beside the power pin can release charge within nanoseconds, keeping the voltage stable. If the capacitor is placed farther away, the trace inductance increases significantly, and the capacitor becomes ineffective at high frequencies. In practical design, a 0.1 µF capacitor is typically used to handle high-frequency transients and switching noise, while larger capacitors such as 1 µF or 10 µF address lower-frequency voltage variations and stabilize the overall supply. Usually, each IC power pin has its own 0.1 µF ceramic capacitor to shunt high-frequency disturbances; an additional 1 µF or 4.7 µF ceramic capacitor is placed nearby to handle mid-frequency energy needs; and a larger 10 µF to 100 µF tantalum or electrolytic capacitor is located at the power input or voltage regulator output to serve as bulk energy storage for low-frequency stability. The decoupling capacitor should be placed as close as possible to both the power and ground pins of the IC, with traces kept short and wide, preferably connected directly to the power and ground planes to minimize loop area and parasitic inductance. Ceramic capacitors, especially those with X7R or X5R dielectric, are ideal for this purpose because they offer low equivalent series inductance (ESL) and low equivalent series resistance (ESR), allowing fast current response. In summary, the location of the 0.1 µF capacitor determines whether it can respond effectively to transient events, while the combination of different capacitor values defines the frequency range the decoupling network can handle. Small capacitors react quickly to high-frequency noise, and larger ones maintain steady voltage over longer timescales. Together, they ensure the IC’s power supply remains clean, stable, and reliable. Attachment : 4.png | |||||
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