[Solved] Setting multiple pins as OUTPUT

For loop will do the job if the pins are in series:

for (int i = 2; i <= 9; i++) { 
pinMode(i, OUTPUT);
}

If pins are random, use an array like this:

int buttons[]={2,4,5,8,10,13};
for(int i:buttons){
pinMode(i, OUTPUT);
}

You can use for loop for this; here's how

for (int i = 2; i <= 9; i++) { 
pinMode(i, OUTPUT);
}

This loop goes from pin 2 to 9 and sets each pin as OUTPUT. 

.

Here's an example using a for loop to configure 8 digital pins (from pin 2 to pin 9) as outputs:

int ledPins[] = {2, 3, 4, 5, 6, 7, 8, 9}; // Array of pin numbers

void setup() {
  for (int i = 0; i < 8; i++) {
    pinMode(ledPins[i], OUTPUT); // Set each pin as an output
  }
}

void loop() {
  // Your code to control LEDs goes here
}

If the pins are not in a series, you can still use an array:

int ledPins[] = {2, 5, 7, 8, 10, 12, 13, A0}; // Array of specific pin numbers

void setup() {
  for (int i = 0; i < 8; i++) {
    pinMode(ledPins[i], OUTPUT); // Set each specified pin as an output
  }
}

void loop() {
  // Your code to control LEDs goes here
}