Notifications
Clear all
Search result for: WA 0859 3970 0884 Pemborong Pasang Plafon PVC Drop Gantung Berpengalaman Girisubo Gunungkidul
Page 2 / 2
Prev
| # | Post Title | Result Info | Date | User | Forum |
| Answer to: How to Locate a Short Circuit on a PCB? | 3 Relevance | 8 months ago | Paul | Theoretical questions | |
| ... the board, lifting one leg of suspected components (like capacitors or diodes) to see if the short clears. Electrolytic caps are a common culprit. Another simple method that’s helped me is the finger test or using a Drop of isopropyl alcohol. Power the board with a current-limited supply (set low, so nothing burns), and often the shorted component will heat up faster than the rest. You can sometimes feel it with your finger or WAtch where the alcohol evaporates first. If the short is stubborn, I’ve also followed the divide and conquer approach—cutting tra ... | |||||
| Answer to: Why Place Decoupling Caps Near ICs? | 3 Relevance | 9 months ago | DIY Electronica | Theoretical questions | |
| Decoupling capacitors are used to stabilize the power supply voltage and reduce noise for integrated circuits (ICs). When an IC switches states (especially fast digital devices), it draws brief but significant bursts of current. If the power supply line cannot deliver this current instantly, the voltage can Drop momentarily, causing instability or even malfunction. Key reasons to place them close to IC pins: Minimizing inductance: The longer the trace between the capacitor and the IC’s power pin, the more inductance is added. Inductance impedes high-frequency currents, preventing the capacitor from delivering energy when needed most. Handling switching current spikes: Fast-switching devices (CMOS, TTL, high-speed analog ICs) create rapid current spikes as internal transistors switch. A nearby decoupling capacitor acts as a local energy reservoir, instantly supplying these bursts of current. Reducing voltage dips and noise: If the capacitor is too far away, high-frequency noise can couple onto the supply line and affect not only the target IC but also other nearby devices. | |||||
| Shift Register Cascading Issues | 3 Relevance | 10 months ago | Electronix | Theoretical questions | |
| I'm trying to cascade multiple 74HC595 shift registers to expand the number of digital outputs in my project. While one shift register works perfectly on its own, as soon as I add the second (and especially the third), I start getting strange or inconsistent output—some LEDs don’t light up correctly, or they shift out of order. Is there a timing issue I might be overlooking? Do I need to delay between latching and shifting? Could signal integrity or voltage Drop be the issue when chaining several ICs? | |||||
| Answer to: Arduino UNO R4 Wi-Fi Project ideas! | 3 Relevance | 1 year ago | Admin | Arduino | |
| ... on a web interface.2. Remote-Controlled LEDs – Create a simple web-based LED controller using the board’s Wi-Fi, allowing you to turn LEDs on/off from your phone.3. Wireless Sensor Hub – Connect multiple sensors (LDR, temperature, gas) and send the data wirelessly to another device using MQTT. Intermediate Projects 4. IoT-Based Smart Lock – Use an RFID module or fingerprint sensor to control a servo-motorized lock, with access logs stored on a cloud database.5. Real-Time Data Logger – Log sensor readings onto an SD card and simultaneously send them to Goo ... | |||||
| Answer to: How to Identify the Neutral Wire Using a Multimeter? | 3 Relevance | 1 year ago | Kanishk | Equipments | |
| This is the safest option to identify the Neutral wire using a multimeter: 1. Set Up Your Multimeter: Set your multimeter to AC voltage mode (V~). Choose a range higher than your supply voltage (e.g., 250V for 220V systems). Insert the black probe in COM and the red probe in V/Ω. 2. Identify the Live Wire: Place the black probe on a known earth source (e.g., a metallic pipe or grounded screw). Use the red probe to measure each wire. Live to Earth = ~220V (or 110V) Neutral to Earth = 0V - 5V Earth to Earth = 0V The wire showing the highest voltage (~220V or 110V) is Live. 3. Identify Neutral vs. Earth: Measure the voltage between the remaining two wires. Neutral to Earth should show 0V - 5V due to minor voltage Drop. Earth to Live should still show ~220V (or 110V). The wire showing nearly 0V relative to Earth is the actual Earth wire. | |||||
| Answer to: How does a boost converter work? | 3 Relevance | 1 year ago | Mehjabeen | Theoretical questions | |
| A boost converter is a type of DC-DC converter that increases voltage while reducing current to maintain energy balance. It operates using an inductor, a switch (transistor), a diode, and a capacitor. When the switch is closed, current flows through the inductor, storing energy in its magnetic field. When the switch opens, the inductor resists the sudden Drop in current and releases its stored energy. This energy combines with the input voltage, resulting in a higher output voltage. The diode ensures current flows in the correct direction, and the capacitor smooths the output voltage for a stable supply. By rapidly switching on and off, the boost converter efficiently steps up the voltage. The extra voltage comes from the inductor’s stored energy, making it useful in applications like battery-powered devices, LED drivers, and power supplies where a higher voltage is required. | |||||
| Answer to: How to Identify the Neutral Wire Using a Multimeter? | 3 Relevance | 1 year ago | Admin | Equipments | |
| Hey there! Here's a quick, step-by-step guide to identifying live, neutral, and earth wires using a digital multimeter: Set Up Your Multimeter:Choose the AC voltage mode and set the range higher than your local supply (e.g., 220V or 110V). Identify the Live Wire: Label your three wires as A, B, and C. Measure the voltage between A and B, B and C, and A and C. The pair that shows ~220V (or 110V) contains the Live and Neutral wires. For example: 220V between A and B i.e., one of them is live. Then, measure between one of these (A) and the third remaining wire (C). If A to C also reads close to 220V (or 110V), then A is likely to live. If it’s much lower (around 1-5V), then the live wire is the other one (B). Determine Neutral vs. Earth: Now measure the voltage between the identified live wire and the remaining two wires i.e., first between A and B, then between A and C The wire with a lower voltage difference (around 1-5V) compared to the live wire is neutral. For example: Bw A and B = 215 and BW A and C = 220. In this case, wire B is neutral The other wire, showing nearly 0V less than the neutral is your Earth i.e., wire C is Earth. Keep in mind: Ideally, live should be around 220V (or 110V), while neutral and earth are close to 0V (with a slight Drop of 1-5V on neutral due to resistance). For a deeper dive and more detailed instructions, check out this article: How to Identify Live, Neutral, and Earth Using a Multimeter. | |||||
| Answer to: Why Fluke multimeters are so expensive? | 3 Relevance | 1 year ago | Neeraj Dev | Equipments | |
| ... designed to provide precise and accurate readings, which are crucial for troubleshooting and validation tasks in both professional and industrial settings. Calibration Standards: These devices meet stringent calibration standards, ensuring consistent and reliable measurements over time. Advanced Features: Fluke includes features such as true-RMS (Root Mean Square) measurement, essential for accurately assessing non-linear loads and modern electronics. 2. Durability and Safety Robust Construction: Fluke multimeters are engineered to withstand harsh environ ... | |||||
| Answer to: BJT VS MOSFET- Current controlled vs Voltage controlled | 3 Relevance | 2 years ago | Tech Geek | Theoretical questions | |
| Maybe this explanation will help: BJT has three regions: emitter, base, and collector, with the emitter and collector, doped to create majority carriers (electrons for NPN, holes for PNP). Applying a forward bias to the base-emitter junction allows majority of carriers to diffuse into the base. Due to the thin and lightly doped base, most carriers don't reach the collector; some recombine within the base, generating a small base current (Ib), while the remainder is injected into the collector, forming the collector current (Ic). While voltage plays a role in creating the forward bias at the base-emitter junction, it's not the direct control factor. The voltage Drop across this junction is relatively constant. It's the current injected due to this voltage that ultimately controls the collector current. Even a small change in base current (Ib) significantly influences the number of carriers injected into the collector, resulting in a current gain (beta, β), hence BJTs are termed current-controlled devices. MOSFET has an insulated gate separated by a thin oxide layer from the channel. When voltage is applied to the gate, it induces an electric field across the oxide, influencing charge carriers in the channel (electrons for NMOS, holes for PMOS), thereby establishing a conductive or resistive region. High gate voltage prompts a strong electric field, creating a low-resistance channel for high current flow, whereas low gate voltage yields a weaker field, resulting in reduced current flow. Voltage modulation of the gate controls the electric field strength, subsequently regulating channel resistance and drain current, with minimal current flow between gate and channel due to insulation. Hence they are voltage controlled devices. | |||||
Page 2 / 2
Prev
